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527-96x+4x^2=0
a = 4; b = -96; c = +527;
Δ = b2-4ac
Δ = -962-4·4·527
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-28}{2*4}=\frac{68}{8} =8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+28}{2*4}=\frac{124}{8} =15+1/2 $
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